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devel / comp.theory / Re: Correcting the definition of the terms of the halting problem[3]

SubjectAuthor
* Correcting the definition of the terms of the halting problemolcott
+* Re: Correcting the definition of the terms of the halting problemRichard Damon
|`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| +* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| | `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |  `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   +* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   | `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  +* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  |+* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  || +* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  || |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  || | +* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  || | |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  || | | `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  || | |  `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  || | |   +* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  || | |   |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  || | |   | `- Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  || | |   `* Re: Correcting the definition of the terms of the halting problem[3]immibis
| |   |  || | |    `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  || | |     +* Re: Correcting the definition of the terms of the halting problem[3]immibis
| |   |  || | |     |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  || | |     | +- Re: Correcting the definition of the terms of the halting problem[3]immibis
| |   |  || | |     | `- Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  || | |     `- Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  || | `- Re: Correcting the definition of the terms of the halting problem[3]immibis
| |   |  || `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||  `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||   +* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||   |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||   | `- Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||   +* Re: Correcting the definition of the terms of the halting problem[3]André G. Isaak
| |   |  ||   |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||   | `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||   |  `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||   |   `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||   |    `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||   |     `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||   |      `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||   |       `* Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||   |        `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |         `* Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |          `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |           +* Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |           |`* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |           | `* Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |           |  `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |           |   +- Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |           |   `* Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |           |    `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |           |     `* Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |           |      `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |           |       +* Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |           |       |+* ---Richard admits simulated DD cannot halt---olcott
| |   |  ||   |           |       ||+* Re: ---Richard admits simulated DD cannot halt---Richard Damon
| |   |  ||   |           |       |||`* Re: ---Richard admits simulated DD cannot halt---(too late)olcott
| |   |  ||   |           |       ||| `* Re: ---Richard admits simulated DD cannot halt---(too late)Richard Damon
| |   |  ||   |           |       |||  `* Re: ---Richard admits simulated DD cannot halt---(too late)olcott
| |   |  ||   |           |       |||   `* Re: ---Richard admits simulated DD cannot halt---(too late)Richard Damon
| |   |  ||   |           |       |||    `- Re: ---Richard admits simulated DD cannot halt---(too late)olcott
| |   |  ||   |           |       ||`* Re: ---Richard admits simulated DD cannot halt---immibis
| |   |  ||   |           |       || `* Re: ---Richard admits simulated DD cannot halt---olcott
| |   |  ||   |           |       ||  `- Re: ---Richard admits simulated DD cannot halt--- But Olcott doesn't understand Richard Damon
| |   |  ||   |           |       |+* ---Richard admits simulated DD cannot halt---olcott
| |   |  ||   |           |       ||`* Re: ---Richard admits simulated DD cannot halt--- But only for the HH that neverRichard Damon
| |   |  ||   |           |       || `* Re: ---Richard admits simulated DD cannot halt--- [7]olcott
| |   |  ||   |           |       ||  `- Re: ---Richard admits simulated DD cannot halt--- [7]Richard Damon
| |   |  ||   |           |       |`* ---Richard admits simulated DD cannot halt---olcott
| |   |  ||   |           |       | `* Re: ---Richard admits simulated DD cannot halt---Richard Damon
| |   |  ||   |           |       |  `* Re: ---Richard admits simulated DD cannot halt---olcott
| |   |  ||   |           |       |   +- Re: ---Richard admits simulated DD cannot halt---Richard Damon
| |   |  ||   |           |       |   `- Re: ---Richard admits simulated DD cannot halt---immibis
| |   |  ||   |           |       `* Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |           |        `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |           |         `- Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |           `* Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |            `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |             `* Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |              `* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |               +* Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |               |`* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |               | +* Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |               | |`* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |               | | +* Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |               | | |`* Re: Correcting the definition of the terms of the halting problem[6]olcott
| |   |  ||   |               | | | +* Re: Correcting the definition of the terms of the halting problem[6]immibis
| |   |  ||   |               | | | |`- Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |               | | | `- Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |               | | `- Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |               | `- Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   |               `- Re: Correcting the definition of the terms of the halting problem[6]Richard Damon
| |   |  ||   `* Re: Correcting the definition of the terms of the halting problem[3]immibis
| |   |  ||    `* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||     +* Re: Correcting the definition of the terms of the halting problem[3]immibis
| |   |  ||     |`* Re: Correcting the definition of the terms of the halting problem[3]olcott
| |   |  ||     | `- Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  ||     `- Re: Correcting the definition of the terms of the halting problem[3]Richard Damon
| |   |  |+* Re: Correcting the definition of the terms of the halting problem[3]immibis
| |   |  |`* Re: Correcting the definition of the terms of the halting problem[3]Alan Mackenzie
| |   |  `* Re: Correcting the definition of the terms of the halting problem[3]Alan Mackenzie
| |   `* Re: Correcting the definition of the terms of the halting problem[3]immibis
| `* Re: Correcting the definition of the terms of the halting problem[3]immibis
`* Re: Correcting the definition of the terms of the halting problemimmibis

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Re: Correcting the definition of the terms of the halting problem[3]

<uog6jo$3kigk$1@dont-email.me>

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From: F.Zwarts@HetNet.nl (Fred. Zwarts)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Date: Sat, 20 Jan 2024 11:17:29 +0100
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 by: Fred. Zwarts - Sat, 20 Jan 2024 10:17 UTC

Op 20.jan.2024 om 01:36 schreef olcott:
> On 1/19/2024 6:08 PM, Richard Damon wrote:

>
> The definition of correct simulation simply presumed
> that pathological self-reference does not change the
> execution sequence because no one ever bothered to
> carefully examined this.
>
> Naive set theory presumed that its definition of {set}
> was correct and ZFC proved that it was not correct.
>
> Since it is a verified fact that D correctly simulated by
> H1 depends on H aborting its simulation and H cannot
> depend on this it is proved that they are not the same.

It is not D that has a pathological self-reference. D has no
self-reference. It is H that has a self-reference. It uses its own address.

It is not D that contradicts itself. It is H that contradicts itself: At
the one hand it says that, when called, it has infinite recursion, but
at the other hand it aborts and returns a result, which is a contradiction.

Olcott wants to reject self-referencing contradictions, so he should
reject H, not D.

Re: Correcting the definition of the terms of the halting problem[3]

<uog804$1a83$1@news.muc.de>

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From: acm@muc.de (Alan Mackenzie)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Followup-To: comp.theory
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 by: Alan Mackenzie - Sat, 20 Jan 2024 10:41 UTC

In comp.theory olcott <polcott2@gmail.com> wrote:
> On 1/19/2024 6:01 PM, Alan Mackenzie wrote:
>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>> On 1/19/2024 4:58 PM, Alan Mackenzie wrote:
>>>> In comp.theory olcott <polcott2@gmail.com> wrote:

[ .... ]

>>>>> In other words no one can possibly tell that the above function
>>>>> will not halt until they waited an infinite amount of time and saw
>>>>> that it did not halt. DUMB, DUMB, DUMB, DUMB.

>>>> That is why attempting to solve the halting problem with a simulator
>>>> is not a sensible thing to do.

>>> The best selling author of textbooks on the theory of computation
>>> disagrees.

>> He does not. This author knows full well that a halting decider
>> cannot be built, as do millions of students and graduates world wide,
>> who have seen a proof (or even written one) and appreciate its
>> clarity, simplicity, and finality.

>>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X

>>> On 10/13/2022 11:46 AM, olcott wrote:
>>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>>> paragraph is correct (he has not agreed to anything else in this
>>>> paper):

>>>> If simulating halt decider H correctly simulates its input D until H
>>>> correctly determines that its simulated D would never stop running
>>>> unless aborted then H can abort its simulation of D and correctly
>>>> report that D specifies a non-halting sequence of configurations.

>>>> When one accepts this definition of a simulating halt decider then
>>>> my code shows that H correctly determines the halt status of D.

>> I haven't seen you define a halting decider of any type over the last
>> few years.

> When you ignore what I say THIS DOES NOT COUNT AS ME NOT SAYING IT.
> Professor Sipser agreed that the following definition of a simulating
> halt decider is correct

It's like the good professor agreeing that if pigs had wings, they would
fly. And you're taking that as a license to discuss the pigs' flying
techniques, their lift to drag ratio, and so on. In reality pigs don't
have wings, and they certainly don't fly.

Professor Sipser said what he had to say to avoid getting drawn into an
interminable time wasting exchange with a crank. He's got other things
to do.

> On 10/13/2022 11:46 AM, olcott wrote:
>> MIT Professor Michael Sipser has agreed that the following verbatim
>> paragraph is correct:

>> If simulating halt decider H correctly simulates its input D until H
>> correctly determines that its simulated D would never stop running
>> unless aborted then H can abort its simulation of D and correctly
>> report that D specifies a non-halting sequence of configurations.

> Did you notice that it says: "simulating halt decider H"

Yes. But you haven't yet noticed that little word "if" at the beginning
of his sentence. There is no such thing as a halt decider, simulating or
otherwise, so you could just as well write "If simulating halt decider H
correctly simulates its input D, then pigs would fly.", and it would be
just as true. But just as meaningless and not at all sensible.

> --
> Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
> hits a target no one else can see." Arthur Schopenhauer

--
Alan Mackenzie (Nuremberg, Germany).

Re: Correcting the definition of the terms of the halting problem[3]

<uogdtg$3trm8$1@i2pn2.org>

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From: richard@damon-family.org (Richard Damon)
Newsgroups: sci.logic,comp.theory
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Date: Sat, 20 Jan 2024 07:22:08 -0500
Organization: i2pn2 (i2pn.org)
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 by: Richard Damon - Sat, 20 Jan 2024 12:22 UTC

On 1/19/24 11:29 PM, olcott wrote:
> On 1/19/2024 10:07 PM, Richard Damon wrote:
>> On 1/19/24 10:28 PM, olcott wrote:
>>> On 1/19/2024 9:13 PM, Richard Damon wrote:
>>>> On 1/19/24 9:55 PM, olcott wrote:
>>>>> On 1/19/2024 8:39 PM, Richard Damon wrote:
>>>>>> On 1/19/24 9:08 PM, olcott wrote:
>>>>>>> On 1/19/2024 7:58 PM, André G. Isaak wrote:
>>>>>>>> On 2024-01-19 18:26, olcott wrote:
>>>>>>>>
>>>>>>>>> The full state of D was repeated.
>>>>>>>>> The only thing that changed was the stack address.
>>>>>>>>
>>>>>>>> The contents of the stack and the stack address are *part* of
>>>>>>>> the state of the machine. If they change, you are not repeating
>>>>>>>> the same state.
>>>>>>>>
>>>>>>>> André
>>>>>>>>
>>>>>>>
>>>>>>> Everything is identical across recursive simulations besides
>>>>>>> the stack address. The stack address is irrelevant to whether
>>>>>>> or not DD halts.
>>>>>>>
>>>>>>
>>>>>> Nope, and part of the problem is you stopped looking at the actual
>>>>>> simulaiton of the input.  The simulator being simulated at the
>>>>>> first call will be in a different state at the second call to H
>>>>>> then it was when it started, just like the outer HH doing the
>>>>>> simulation has built up the history shown.
>>>>>>
>>>>>> That means that, if we continued an actual correct simulation of
>>>>>> this exact input (and thus didn't change HH, but gave the input to
>>>>>> a proper UTM simulator) we would see that the first simulated HH
>>>>>> would run one more level of simulation, and then abort its
>>>>>> simulation, and then return to DD and it would halt.
>>>>>>
>>>>>> Thus, your simulation just isn't showing the actual "state" of the
>>>>>> program (in fact, you arn't even showing the state of the program,
>>>>>> since the key state for this program is what is happening in the
>>>>>> HH that DD is calling)
>>>>>>
>>>>>> The "recursive" layer SHOULD be showing up as the instruction
>>>>>> sequence of the simulator simulating those instructions, and thus
>>>>>> showing that state being generated.
>>>>>>
>>>>>> That second layer never actually shows as a direct simulation in
>>>>>> the proper simulation of the input, except maybe as interspresed
>>>>>> comment of the simulated HH just simulated this instruction.
>>>>>>
>>>>>> If you are going to try to abstract out that simulation, you need
>>>>>> to do it properly, and that means that the simulation level IS
>>>>>> part of state.
>>>>>>
>>>>>>> The easily verified fact that DD simulated by HH cannot possibly
>>>>>>> reach its own simulated final state conclusively proves that DD
>>>>>>> does not halt.
>>>>>>
>>>>>> No, that only hold *IF* HH correctly simulates the input, which
>>>>>> means that HH can NEVER abort its simulation.
>>>>>>
>>>>>>>
>>>>>>> Begin Local Halt Decider Simulation        Execution Trace Stored
>>>>>>> at:113027
>>>>>>> [00001c42][00113013][00113017] 55          push ebp
>>>>>>> [00001c43][00113013][00113017] 8bec        mov ebp,esp
>>>>>>> [00001c45][0011300f][00102fe3] 51          push ecx
>>>>>>> [00001c46][0011300f][00102fe3] 8b4508      mov eax,[ebp+08] ; DD
>>>>>>> [00001c49][0011300b][00001c42] 50          push eax         ; DD
>>>>>>> [00001c4a][0011300b][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
>>>>>>> [00001c4d][00113007][00001c42] 51          push ecx         ; DD
>>>>>>> [00001c4e][00113003][00001c53] e80ff7ffff  call 00001362    ; HH
>>>>>>> New slave_stack at:14da47
>>>>>>
>>>>>> Note. error in simulation here. Call to HH should be showing the
>>>>>> states of operation of HH
>>>>>>
>>>>>
>>>>> Tell me how the behavior of HH can possibly show that
>>>>> DD reaches its final state and I will provide a link
>>>>> with the 151 pages of the execution trace of HH.
>>>>
>>>> It can't in its simulation, but an actually correct simulation of
>>>> the input, which HH doesn't do, can.
>>>
>>> *When I challenge you to show what the correct detailed*
>>> *line-by-line machine address by machine address steps*
>>> *SHOULD BE you consistently utterly fail because you really*
>>> *don't know Jack about these things and are just bluffing*
>>
>> i.e. I'm not falling for your strawman and are panicing as badly as
>> your buddy Trump.
> Trump is a Hitler wanna bee.

Yep, and you are no better.

You use the same lying techniques as he does, even though you CLAIM to
be fighting those techniques (that makes you the Hypocrite)

>
> *You failed try again*
> I show 16 lines of machine code
> *you must show ever detail of your corrected machine code*
> *This must include the machine address and the assembly language*

Why?

>
> *OR YOU FAIL*
> *OR YOU FAIL*
> *OR YOU FAIL*
> *OR YOU FAIL*

NOPE!!!

YOU have failed, but are apparently so brain dead the news can't get to you.

>
> *When I challenge you to show what the correct detailed*
> *line-by-line machine address by machine address steps*
> *SHOULD BE you consistently utterly fail because you really*
> *don't know Jack about these things and are just bluffing*

And why do YOU have the power to dictate how I argue?

Tell me what was wrong with what I said?

Is the problem that your rote mind can't comprehend what I say?

Your failure to answer the points made, just show that you don't have
answers and are resorting to Strawmen.

>
> Begin Local Halt Decider Simulation        Execution Trace Stored at:113027
>
>  machine   stack     stack     machine    assembly
>  address   address   data      code       language
>  ========  ========  ========  =========  =============
> [00001c42][00113013][00113017] 55          push ebp
> [00001c43][00113013][00113017] 8bec        mov ebp,esp
> [00001c45][0011300f][00102fe3] 51          push ecx
> [00001c46][0011300f][00102fe3] 8b4508      mov eax,[ebp+08] ; DD
> [00001c49][0011300b][00001c42] 50          push eax         ; DD
> [00001c4a][0011300b][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
> [00001c4d][00113007][00001c42] 51          push ecx         ; DD
> [00001c4e][00113003][00001c53] e80ff7ffff  call 00001362    ; HH
> New slave_stack at:14da47
> [00001c42][0015da3b][0015da3f] 55          push ebp
> [00001c43][0015da3b][0015da3f] 8bec        mov ebp,esp
> [00001c45][0015da37][0014da0b] 51          push ecx
> [00001c46][0015da37][0014da0b] 8b4508      mov eax,[ebp+08] ; DD
> [00001c49][0015da33][00001c42] 50          push eax         ; DD
> [00001c4a][0015da33][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
> [00001c4d][0015da2f][00001c42] 51          push ecx         ; DD
> [00001c4e][0015da2b][00001c53] e80ff7ffff  call 00001362    ; HH
> Local Halt Decider: Recursion Simulation Detected Simulation Stopped
>
> _DD()
> [00001c42] 55         push ebp
> [00001c43] 8bec       mov ebp,esp
> [00001c45] 51         push ecx
> [00001c46] 8b4508     mov eax,[ebp+08] ; DD
> [00001c49] 50         push eax         ; DD
> [00001c4a] 8b4d08     mov ecx,[ebp+08] ; DD
> [00001c4d] 51         push ecx         ; DD
> [00001c4e] e80ff7ffff call 00001362    ; HH
> [00001c53] 83c408     add esp,+08
> [00001c56] 8945fc     mov [ebp-04],eax
> [00001c59] 837dfc00   cmp dword [ebp-04],+00
> [00001c5d] 7402       jz 00001c61
> [00001c5f] ebfe       jmp 00001c5f
> [00001c61] 8b45fc     mov eax,[ebp-04]
> [00001c64] 8be5       mov esp,ebp
> [00001c66] 5d         pop ebp
> [00001c67] c3         ret
> Size in bytes:(0038) [00001c67]
>
>


Click here to read the complete article
Re: Correcting the definition of the terms of the halting problem[3]

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From: richard@damon-family.org (Richard Damon)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Date: Sat, 20 Jan 2024 07:23:53 -0500
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 by: Richard Damon - Sat, 20 Jan 2024 12:23 UTC

On 1/20/24 5:17 AM, Fred. Zwarts wrote:
> Op 20.jan.2024 om 01:36 schreef olcott:
>> On 1/19/2024 6:08 PM, Richard Damon wrote:
>
>>
>> The definition of correct simulation simply presumed
>> that pathological self-reference does not change the
>> execution sequence because no one ever bothered to
>> carefully examined this.
>>
>> Naive set theory presumed that its definition of {set}
>> was correct and ZFC proved that it was not correct.
>>
>> Since it is a verified fact that D correctly simulated by
>> H1 depends on H aborting its simulation and H cannot
>> depend on this it is proved that they are not the same.
>
> It is not D that has a pathological self-reference. D has no
> self-reference. It is H that has a self-reference. It uses its own address.
>
> It is not D that contradicts itself. It is H that contradicts itself: At
> the one hand it says that, when called, it has infinite recursion, but
> at the other hand it aborts and returns a result, which is a contradiction.
>
> Olcott wants to reject self-referencing contradictions, so he should
> reject H, not D.
>

Actually, in his system Neither D or H are actually complete programs by
themselves, but we need to make one combined program for the combination.

He has changed the definition of D in a subtle way that makes it no
longer a computation and having a Reference in it to H, which becomes,
through H, and then H turns that into the pathological self-reference.

D no longer is built on the specific H that is being claimed to be
correct, but whatever H, from an infinite set of possible Hs, is
currently "in view"/

This shows up in his arguments as neither D or H are actual programs but
"Sets" of program/data pairs varied by what-ever H he wants the code of
H to be at the moment.

This of course reveals that there IS NO H that meets the requriments,
even the requirement that he has made up. The H that answers doesn't
"Correctly Deteremine that its own Correct Simulation would not Halt",
as that H never does a correct simulation, but instead refers to a
DIFFERENT H's, using a DIFFERENT D (since it is calling a different H)
simualation of that different input.

The fact that the base subroutine "D" didn't change makes hm claim it is
the same input (since that is all that H takes), but that makes D not a
program.

This is also the reason his simulation jumps levels, he is only
simulating the code in the function D itself and not the calls to H,
ignoring that the H is actually part of the definition of the program D.

This is all part of his lie of PO-Halting Problem in PO-Computation
Theory as part of PO-Logic, that he refuses to acknoledge he is talking
in, because he is just to stupid (and arrogant) to follow the rules.

Re: Correcting the definition of the terms of the halting problem[5]

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From: polcott2@gmail.com (olcott)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[5]
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 by: olcott - Sat, 20 Jan 2024 14:50 UTC

On 1/20/2024 4:17 AM, Fred. Zwarts wrote:
> Op 20.jan.2024 om 01:36 schreef olcott:
>> On 1/19/2024 6:08 PM, Richard Damon wrote:
>
>>
>> The definition of correct simulation simply presumed
>> that pathological self-reference does not change the
>> execution sequence because no one ever bothered to
>> carefully examined this.
>>
>> Naive set theory presumed that its definition of {set}
>> was correct and ZFC proved that it was not correct.
>>
>> Since it is a verified fact that D correctly simulated by
>> H1 depends on H aborting its simulation and H cannot
>> depend on this it is proved that they are not the same.
>
> It is not D that has a pathological self-reference. D has no
> self-reference. It is H that has a self-reference. It uses its own address.
>

*D specifies that it calls its own termination analyzer*
*so you are wrong, D was intentionally defined to thwart H*

> It is not D that contradicts itself. It is H that contradicts itself: At
> the one hand it says that, when called, it has infinite recursion, but
> at the other hand it aborts and returns a result, which is a contradiction.

DD correctly simulated by HH is a different computation
than the directly executed DD(DD).

This is proven by their differing execution traces:
(a) DD simulated by HH cannot possibly reach its own final state.
(b) The directly executed DD(DD) does reach its own final state.

*That people disagree with execution traces is a little nutty*
*It is like disagreeing with arithmetic*

That people disagree with the execution trace of DD correctly
simulated by HH yet will not show how to correct it is a little
deceitful. It is like they know they are wrong and refuse to admit it.

>
> Olcott wants to reject self-referencing contradictions, so he should
> reject H, not D.
>

*D was intentionally defined to thwart H so the fault lies with D*

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
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 by: olcott - Sat, 20 Jan 2024 14:59 UTC

On 1/20/2024 4:41 AM, Alan Mackenzie wrote:
> In comp.theory olcott <polcott2@gmail.com> wrote:
>> On 1/19/2024 6:01 PM, Alan Mackenzie wrote:
>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>> On 1/19/2024 4:58 PM, Alan Mackenzie wrote:
>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>
> [ .... ]
>
>>>>>> In other words no one can possibly tell that the above function
>>>>>> will not halt until they waited an infinite amount of time and saw
>>>>>> that it did not halt. DUMB, DUMB, DUMB, DUMB.
>
>>>>> That is why attempting to solve the halting problem with a simulator
>>>>> is not a sensible thing to do.
>
>>>> The best selling author of textbooks on the theory of computation
>>>> disagrees.
>
>>> He does not. This author knows full well that a halting decider
>>> cannot be built, as do millions of students and graduates world wide,
>>> who have seen a proof (or even written one) and appreciate its
>>> clarity, simplicity, and finality.
>
>>>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X
>
>>>> On 10/13/2022 11:46 AM, olcott wrote:
>>>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>>>> paragraph is correct (he has not agreed to anything else in this
>>>>> paper):
>
>>>>> If simulating halt decider H correctly simulates its input D until H
>>>>> correctly determines that its simulated D would never stop running
>>>>> unless aborted then H can abort its simulation of D and correctly
>>>>> report that D specifies a non-halting sequence of configurations.
>
>>>>> When one accepts this definition of a simulating halt decider then
>>>>> my code shows that H correctly determines the halt status of D.
>
>>> I haven't seen you define a halting decider of any type over the last
>>> few years.
>
>> When you ignore what I say THIS DOES NOT COUNT AS ME NOT SAYING IT.
>> Professor Sipser agreed that the following definition of a simulating
>> halt decider is correct
>
> It's like the good professor agreeing that if pigs had wings,
> they would fly.

Not at all. He would not risk his credibility that way.
He gave me permission to quote him.

> And you're taking that as a license to discuss the pigs' flying
> techniques, their lift to drag ratio, and so on. In reality pigs don't
> have wings, and they certainly don't fly.
>
> Professor Sipser said what he had to say to avoid getting drawn into an
> interminable time wasting exchange with a crank. He's got other things
> to do.
>

I told him that I waited two years before I first called him
so that I did not waste his time. He agreed that I could
quote him, he would not have done that if he thought what
he was agreeing to was nonsense.

>> On 10/13/2022 11:46 AM, olcott wrote:
>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>> paragraph is correct:
>
>>> If simulating halt decider H correctly simulates its input D until H
>>> correctly determines that its simulated D would never stop running
>>> unless aborted then H can abort its simulation of D and correctly
>>> report that D specifies a non-halting sequence of configurations.
>
>> Did you notice that it says: "simulating halt decider H"
>
> Yes. But you haven't yet noticed that little word "if" at the beginning
> of his sentence. There is no such thing as a halt decider, simulating or
> otherwise, so you could just as well write "If simulating halt decider H
> correctly simulates its input D, then pigs would fly.", and it would be
> just as true. But just as meaningless and not at all sensible.
>

Technically in my case it is a partial halt decider or a termination
analyzer. Professor Sipser knew that he was only agreeing that a
specific H/D pair would be decidable as non-halting when the criteria
has been met.

Here is my updated paraphrase of (a)
(a) If simulating termination analyzer H correctly determines that D
correctly simulated by H cannot possibly reach its own simulated final
state and terminate normally then

>> --
>> Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
>> hits a target no one else can see." Arthur Schopenhauer
>

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[6]

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 by: olcott - Sat, 20 Jan 2024 15:12 UTC

On 1/20/2024 6:22 AM, Richard Damon wrote:
> On 1/19/24 11:29 PM, olcott wrote:
>> On 1/19/2024 10:07 PM, Richard Damon wrote:
>>> On 1/19/24 10:28 PM, olcott wrote:
>>>> On 1/19/2024 9:13 PM, Richard Damon wrote:
>>>>> On 1/19/24 9:55 PM, olcott wrote:
>>>>>> On 1/19/2024 8:39 PM, Richard Damon wrote:
>>>>>>> On 1/19/24 9:08 PM, olcott wrote:
>>>>>>>> On 1/19/2024 7:58 PM, André G. Isaak wrote:
>>>>>>>>> On 2024-01-19 18:26, olcott wrote:
>>>>>>>>>
>>>>>>>>>> The full state of D was repeated.
>>>>>>>>>> The only thing that changed was the stack address.
>>>>>>>>>
>>>>>>>>> The contents of the stack and the stack address are *part* of
>>>>>>>>> the state of the machine. If they change, you are not repeating
>>>>>>>>> the same state.
>>>>>>>>>
>>>>>>>>> André
>>>>>>>>>
>>>>>>>>
>>>>>>>> Everything is identical across recursive simulations besides
>>>>>>>> the stack address. The stack address is irrelevant to whether
>>>>>>>> or not DD halts.
>>>>>>>>
>>>>>>>
>>>>>>> Nope, and part of the problem is you stopped looking at the
>>>>>>> actual simulaiton of the input.  The simulator being simulated at
>>>>>>> the first call will be in a different state at the second call to
>>>>>>> H then it was when it started, just like the outer HH doing the
>>>>>>> simulation has built up the history shown.
>>>>>>>
>>>>>>> That means that, if we continued an actual correct simulation of
>>>>>>> this exact input (and thus didn't change HH, but gave the input
>>>>>>> to a proper UTM simulator) we would see that the first simulated
>>>>>>> HH would run one more level of simulation, and then abort its
>>>>>>> simulation, and then return to DD and it would halt.
>>>>>>>
>>>>>>> Thus, your simulation just isn't showing the actual "state" of
>>>>>>> the program (in fact, you arn't even showing the state of the
>>>>>>> program, since the key state for this program is what is
>>>>>>> happening in the HH that DD is calling)
>>>>>>>
>>>>>>> The "recursive" layer SHOULD be showing up as the instruction
>>>>>>> sequence of the simulator simulating those instructions, and thus
>>>>>>> showing that state being generated.
>>>>>>>
>>>>>>> That second layer never actually shows as a direct simulation in
>>>>>>> the proper simulation of the input, except maybe as interspresed
>>>>>>> comment of the simulated HH just simulated this instruction.
>>>>>>>
>>>>>>> If you are going to try to abstract out that simulation, you need
>>>>>>> to do it properly, and that means that the simulation level IS
>>>>>>> part of state.
>>>>>>>
>>>>>>>> The easily verified fact that DD simulated by HH cannot possibly
>>>>>>>> reach its own simulated final state conclusively proves that DD
>>>>>>>> does not halt.
>>>>>>>
>>>>>>> No, that only hold *IF* HH correctly simulates the input, which
>>>>>>> means that HH can NEVER abort its simulation.
>>>>>>>
>>>>>>>>
>>>>>>>> Begin Local Halt Decider Simulation        Execution Trace
>>>>>>>> Stored at:113027
>>>>>>>> [00001c42][00113013][00113017] 55          push ebp
>>>>>>>> [00001c43][00113013][00113017] 8bec        mov ebp,esp
>>>>>>>> [00001c45][0011300f][00102fe3] 51          push ecx
>>>>>>>> [00001c46][0011300f][00102fe3] 8b4508      mov eax,[ebp+08] ; DD
>>>>>>>> [00001c49][0011300b][00001c42] 50          push eax         ; DD
>>>>>>>> [00001c4a][0011300b][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
>>>>>>>> [00001c4d][00113007][00001c42] 51          push ecx         ; DD
>>>>>>>> [00001c4e][00113003][00001c53] e80ff7ffff  call 00001362    ; HH
>>>>>>>> New slave_stack at:14da47
>>>>>>>
>>>>>>> Note. error in simulation here. Call to HH should be showing the
>>>>>>> states of operation of HH
>>>>>>>
>>>>>>
>>>>>> Tell me how the behavior of HH can possibly show that
>>>>>> DD reaches its final state and I will provide a link
>>>>>> with the 151 pages of the execution trace of HH.
>>>>>
>>>>> It can't in its simulation, but an actually correct simulation of
>>>>> the input, which HH doesn't do, can.
>>>>
>>>> *When I challenge you to show what the correct detailed*
>>>> *line-by-line machine address by machine address steps*
>>>> *SHOULD BE you consistently utterly fail because you really*
>>>> *don't know Jack about these things and are just bluffing*
>>>
>>> i.e. I'm not falling for your strawman and are panicing as badly as
>>> your buddy Trump.
>> Trump is a Hitler wanna bee.
>
> Yep, and you are no better.
>
> You use the same lying techniques as he does, even though you CLAIM to
> be fighting those techniques (that makes you the Hypocrite)
>
>>
>> *You failed try again*
>> I show 16 lines of machine code
>> *you must show ever detail of your corrected machine code*
>> *This must include the machine address and the assembly language*
>
>
> Why?
>
>
>>
>> *OR YOU FAIL*
>> *OR YOU FAIL*
>> *OR YOU FAIL*
>> *OR YOU FAIL*
>
>
> NOPE!!!
>
> YOU have failed, but are apparently so brain dead the news can't get to
> you.
>
>
>>
>> *When I challenge you to show what the correct detailed*
>> *line-by-line machine address by machine address steps*
>> *SHOULD BE you consistently utterly fail because you really*
>> *don't know Jack about these things and are just bluffing*
>
> And why do YOU have the power to dictate how I argue?
>
> Tell me what was wrong with what I said?

I gave you a complete 16 line execution trace with every single
detail 100% fully specified. You must show exactly which details
of this trace are wrong by correcting these exact details.

*I need to see column (1) and column (5) exact and complete details*
cut-and-paste would also preserve column(4)

The trace that you provide must correspond to the provided
assembly language/machine-code of DD at the bottom.

YOU SAY THAT DD IS NOT CORRECTLY SIMULATED BY HH
I SAY PROVE IT

Begin Local Halt Decider Simulation Execution Trace Stored at:113027
machine stack stack machine assembly
address address data code language
======== ======== ======== ========= =============
Begin Local Halt Decider Simulation Execution Trace Stored at:113027
[00001c42][00113013][00113017] 55 push ebp
[00001c43][00113013][00113017] 8bec mov ebp,esp
[00001c45][0011300f][00102fe3] 51 push ecx
[00001c46][0011300f][00102fe3] 8b4508 mov eax,[ebp+08] ; DD
[00001c49][0011300b][00001c42] 50 push eax ; DD
[00001c4a][0011300b][00001c42] 8b4d08 mov ecx,[ebp+08] ; DD
[00001c4d][00113007][00001c42] 51 push ecx ; DD
[00001c4e][00113003][00001c53] e80ff7ffff call 00001362 ; HH
New slave_stack at:14da47
[00001c42][0015da3b][0015da3f] 55 push ebp
[00001c43][0015da3b][0015da3f] 8bec mov ebp,esp
[00001c45][0015da37][0014da0b] 51 push ecx
[00001c46][0015da37][0014da0b] 8b4508 mov eax,[ebp+08] ; DD
[00001c49][0015da33][00001c42] 50 push eax ; DD
[00001c4a][0015da33][00001c42] 8b4d08 mov ecx,[ebp+08] ; DD
[00001c4d][0015da2f][00001c42] 51 push ecx ; DD
[00001c4e][0015da2b][00001c53] e80ff7ffff call 00001362 ; HH
Local Halt Decider: Recursion Simulation Detected Simulation Stopped


Click here to read the complete article
Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: sci.logic,comp.theory
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Date: Sat, 20 Jan 2024 09:25:48 -0600
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 by: olcott - Sat, 20 Jan 2024 15:25 UTC

On 1/20/2024 4:01 AM, immibis wrote:
> On 1/19/24 23:46, olcott wrote:
>> On 1/19/2024 4:40 PM, immibis wrote:
>>> On 1/19/24 23:22, olcott wrote:
>>>> On 1/19/2024 3:41 PM, immibis wrote:
>>>>> On 1/19/24 22:12, olcott wrote:
>>>>>> On 1/19/2024 2:44 PM, immibis wrote:
>>>>>>> On 1/19/24 19:56, olcott wrote:
>>>>>>>> On 1/19/2024 12:16 PM, immibis wrote:
>>>>>>>>> On 1/19/24 17:14, olcott wrote:
>>>>>>>>>> On 1/19/2024 9:34 AM, Richard Damon wrote:
>>>>>>>>>>> On 1/19/24 8:54 AM, olcott wrote:
>>>>>>>>>>>> *This is the correct definition of a decider*
>>>>>>>>>>>> Deciders always must compute the mapping from an input
>>>>>>>>>>>> finite string to
>>>>>>>>>>>> their own accept or reject state on the basis of a syntactic
>>>>>>>>>>>> or semantic
>>>>>>>>>>>> property of this finite string.
>>>>>>>>>>>>
>>>>>>>>>>>> *Definition of the HP based on the above definition of a
>>>>>>>>>>>> decider*
>>>>>>>>>>>> In computability theory, the halting problem is the problem of
>>>>>>>>>>>> determining, whether an input finite string pair of
>>>>>>>>>>>> program/input
>>>>>>>>>>>> specifies a computation that would reach a final state and
>>>>>>>>>>>> terminate
>>>>>>>>>>>> normally.
>>>>>>>>>>>>
>>>>>>>>>>>> *Definition of halt decider based on the above definitions*
>>>>>>>>>>>> (a) If simulating termination analyzer H correctly
>>>>>>>>>>>> determines that D
>>>>>>>>>>>> correctly simulated by H cannot possibly reach its own
>>>>>>>>>>>> simulated final
>>>>>>>>>>>> state and terminate normally then
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> Nope.
>>>>>>>>>>>
>>>>>>>>>>> Where did you get the transition from
>>>>>>>>>>>
>>>>>>>>>>> a input finite string pair of program/input specifies a
>>>>>>>>>>> computation that would reach a final state and terminate
>>>>>>>>>>> normally
>>>>>>>>>>>
>>>>>>>>>>> to
>>>>>>>>>>>
>>>>>>>>>>> H correctly determines that D correctly simulated *by H*
>>>>>>>>>>> cannot possiby reach its own simulated final state.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> The computation that D specifies to H <is> recursive
>>>>>>>>>> simulation. H is not allowed to simply ignore that D
>>>>>>>>>> is calling itself.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> H is not allowed to simply ignore that D would detect infinite
>>>>>>>>> recursion, stop simulating and reach a final state.
>>>>>>>>>
>>>>>>>>
>>>>>>>> *This is simply over your head*
>>>>>>>> Unless the outermost HH aborts its simulation then none of them do.
>>>>>>>>
>>>>>>>
>>>>>>> Why?
>>>>>>>
>>>>>>
>>>>>> Each simulated HH has the exact same instructions as the
>>>>>> others because it <is> the same code at the same machine
>>>>>> address.
>>>>>
>>>>> Does the direct executed HH have the exact same instructions as
>>>>> each simulated HH?
>>>>>
>>>>
>>>> There is only one HH at machine address [00001032].
>>>>
>>>
>>> Does the direct executed HH have the exact same instructions as each
>>> simulated HH?
>>
>> There is only one HH at machine address [00001032].
>> There is only one HH at machine address [00001032].
>> There is only one HH at machine address [00001032].
>> There is only one HH at machine address [00001032].
>> There is only one HH at machine address [00001032].
>>
>> You must have ADD like Richard. I have to repeat
>> things to Richard hundreds of times before he ever
>> notices that I said them once.
>>
>
> Why can't you answer the question?

I answered the question with all of the technical details
that prove the answer. If there is only one thing in the
universe then is this thing different than itself?

There is only one HH in Halt7.c and it is never copied.

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: sci.logic,comp.theory
Subject: Re: Correcting the definition of the terms of the halting problem[3]
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 by: olcott - Sat, 20 Jan 2024 15:33 UTC

On 1/20/2024 4:02 AM, immibis wrote:
> On 1/20/24 02:14, olcott wrote:
>>
>> It is not about solving arbitrary problems it is about
>> being able to perfectly understand how execution traces
>> work and how they can be verified as correct.
>>
>> You are clearly not very good at that problem.
>>
>
> And how they can be verified as incorrect.

See my 9:12 AM reply to Richard
it has too many details to keep repeating.
Message-ID: <uognsk$3nggk$1@dont-email.me>

http://al.howardknight.net/
Usenet Article Lookup
<uognsk$3nggk$1@dont-email.me>

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: sci.logic,comp.theory
Subject: Re: Correcting the definition of the terms of the halting problem[3]
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 by: olcott - Sat, 20 Jan 2024 15:38 UTC

On 1/20/2024 4:04 AM, immibis wrote:
> On 1/20/24 01:55, olcott wrote:
>>
>> Begin Local Halt Decider Simulation        Execution Trace Stored
>> at:113027
>> [00001c42][00113013][00113017] 55          push ebp
>> [00001c43][00113013][00113017] 8bec        mov ebp,esp
>> [00001c45][0011300f][00102fe3] 51          push ecx
>> [00001c46][0011300f][00102fe3] 8b4508      mov eax,[ebp+08] ; DD
>> [00001c49][0011300b][00001c42] 50          push eax         ; DD
>> [00001c4a][0011300b][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
>> [00001c4d][00113007][00001c42] 51          push ecx         ; DD
>> [00001c4e][00113003][00001c53] e80ff7ffff  call 00001362    ; HH
>> New slave_stack at:14da47
>> [00001c42][0015da3b][0015da3f] 55          push ebp
>> [00001c43][0015da3b][0015da3f] 8bec        mov ebp,esp
>> [00001c45][0015da37][0014da0b] 51          push ecx
>> [00001c46][0015da37][0014da0b] 8b4508      mov eax,[ebp+08] ; DD
>> [00001c49][0015da33][00001c42] 50          push eax         ; DD
>> [00001c4a][0015da33][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
>> [00001c4d][0015da2f][00001c42] 51          push ecx         ; DD
>> [00001c4e][0015da2b][00001c53] e80ff7ffff  call 00001362    ; HH
>> Local Halt Decider: Recursion Simulation Detected Simulation Stopped
>>
>> That you cannot tell that the above specifies
>> non-halting behavior makes you a dunderhead.
>>
>
> This trace dishonestly ignores the instructions that tell HH to check
> for non-halting repeated patterns.

Nothing that HH can possibly do can cause DD correctly
simulated by HH to reach its own simulated final state.

Anyone that does not know this is unqualified to review
my work.

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
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Subject: Re: Correcting the definition of the terms of the halting problem[3]
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 by: olcott - Sat, 20 Jan 2024 15:43 UTC

On 1/20/2024 4:04 AM, immibis wrote:
> On 1/20/24 02:26, olcott wrote:
>>
>> The full state of D was repeated.
>> The only thing that changed was the stack address.
>>
> You think the stack address doesn't matter?

That each process context has its own stack cannot possibly
have any effect on the halt status determination.

That you don't know this proves that you are insufficiently
technically competent to review my work.

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: acm@muc.de (Alan Mackenzie)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Followup-To: comp.theory
Date: Sat, 20 Jan 2024 15:43:36 -0000 (UTC)
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 by: Alan Mackenzie - Sat, 20 Jan 2024 15:43 UTC

In comp.theory olcott <polcott2@gmail.com> wrote:
> On 1/20/2024 4:41 AM, Alan Mackenzie wrote:
>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>> On 1/19/2024 6:01 PM, Alan Mackenzie wrote:
>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>>> On 1/19/2024 4:58 PM, Alan Mackenzie wrote:
>>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:

>> [ .... ]

>>>>>>> In other words no one can possibly tell that the above function
>>>>>>> will not halt until they waited an infinite amount of time and saw
>>>>>>> that it did not halt. DUMB, DUMB, DUMB, DUMB.

>>>>>> That is why attempting to solve the halting problem with a simulator
>>>>>> is not a sensible thing to do.

>>>>> The best selling author of textbooks on the theory of computation
>>>>> disagrees.

>>>> He does not. This author knows full well that a halting decider
>>>> cannot be built, as do millions of students and graduates world wide,
>>>> who have seen a proof (or even written one) and appreciate its
>>>> clarity, simplicity, and finality.

>>>>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X

>>>>> On 10/13/2022 11:46 AM, olcott wrote:
>>>>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>>>>> paragraph is correct (he has not agreed to anything else in this
>>>>>> paper):

>>>>>> If simulating halt decider H correctly simulates its input D until H
>>>>>> correctly determines that its simulated D would never stop running
>>>>>> unless aborted then H can abort its simulation of D and correctly
>>>>>> report that D specifies a non-halting sequence of configurations.

>>>>>> When one accepts this definition of a simulating halt decider then
>>>>>> my code shows that H correctly determines the halt status of D.

>>>> I haven't seen you define a halting decider of any type over the last
>>>> few years.

>>> When you ignore what I say THIS DOES NOT COUNT AS ME NOT SAYING IT.
>>> Professor Sipser agreed that the following definition of a simulating
>>> halt decider is correct

>> It's like the good professor agreeing that if pigs had wings,
>> they would fly.

> Not at all. He would not risk his credibility that way.
> He gave me permission to quote him.

He would not be risking his credibility. All professional
mathematicians, and probably most academics, are subject to crank
attacks. I'm sure Ben could confirm this, were he still here. His
colleagues will understand his way of dealing with you, and have sympathy
and empathy with him. What he wrote, what you continually quote, was not
untrue. It's just you haven't understood it.

>> And you're taking that as a license to discuss the pigs' flying
>> techniques, their lift to drag ratio, and so on. In reality pigs don't
>> have wings, and they certainly don't fly.

>> Professor Sipser said what he had to say to avoid getting drawn into an
>> interminable time wasting exchange with a crank. He's got other things
>> to do.

> I told him that I waited two years before I first called him
> so that I did not waste his time. He agreed that I could
> quote him, he would not have done that if he thought what
> he was agreeing to was nonsense.

How not? Given that he just wanted to get rid of you and get back to his
work, he agreed to some harmless nonsense. Apparently this worked well.

>>> On 10/13/2022 11:46 AM, olcott wrote:
>>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>>> paragraph is correct:

>>>> If simulating halt decider H correctly simulates its input D until H
>>>> correctly determines that its simulated D would never stop running
>>>> unless aborted then H can abort its simulation of D and correctly
>>>> report that D specifies a non-halting sequence of configurations.

>>> Did you notice that it says: "simulating halt decider H"

>> Yes. But you haven't yet noticed that little word "if" at the beginning
>> of his sentence. There is no such thing as a halt decider, simulating or
>> otherwise, so you could just as well write "If simulating halt decider H
>> correctly simulates its input D, then pigs would fly.", and it would be
>> just as true. But just as meaningless and not at all sensible.

> Technically in my case it is a partial halt decider or a termination
> analyzer.

Over the months, your claim has varied. Clarity is not your strong
point. You have frequently claimed the impossible halting decider, but
when that claim is challenged, you swerve into a partial halt decider as
you are doing now.

Why don't you now state clearly that you accept the impossibility of a
halting decider, as understood in the computability field? This might
save you a lot of abuse from Richard.

> Professor Sipser knew that he was only agreeing that a specific H/D
> pair would be decidable as non-halting when the criteria has been met.

The professor knew he was dealing with a crank, and said something which
was pedantically true to get you off his back.

> Here is my updated paraphrase of (a)
> (a) If simulating termination analyzer H correctly determines that D
> correctly simulated by H cannot possibly reach its own simulated final
> state and terminate normally then

As I said, clarity is not your strong point. The effect of all these
"correctly"s is to make the statement inane - they're get out clauses.
If you had the courage to write "The simulating termination analyser H
determines that D simulated by H cannot reach ...." then you would be
saying something definite (although probably false).

> --
> Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
> hits a target no one else can see." Arthur Schopenhauer

--
Alan Mackenzie (Nuremberg, Germany).

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Date: Sat, 20 Jan 2024 09:47:31 -0600
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 by: olcott - Sat, 20 Jan 2024 15:47 UTC

On 1/20/2024 4:06 AM, immibis wrote:
> On 1/20/24 00:30, olcott wrote:
>> On 1/19/2024 4:58 PM, Alan Mackenzie wrote:
>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>
>>> [ .... ]
>>>
>>>> void Infinite_Loop()
>>>> {
>>>>    HERE: goto HERE;
>>>> }
>>>
>>>> In other words no one can possibly tell that the above function will
>>>> not
>>>> halt until they waited an infinite amount of time and saw that it did
>>>> not halt. DUMB, DUMB, DUMB, DUMB.
>>>
>>> That is why attempting to solve the halting problem with a simulator is
>>> not a sensible thing to do.
>>>
>>
>> The best selling author of textbooks on the theory of computation
>> disagrees.
>>
>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X
>>
>> On 10/13/2022 11:46 AM, olcott wrote:
>>  > MIT Professor Michael Sipser has agreed that the following
>>  > verbatim paragraph is correct (he has not agreed to anything
>>  > else in this paper):
>>  >
>>  > If simulating halt decider H correctly simulates its input D
>>  > until H correctly determines that its simulated D would never
>>  > stop running unless aborted then H can abort its simulation
>>  > of D and correctly report that D specifies a non-halting
>>  > sequence of configurations.
>>  >
>>  > When one accepts this definition of a simulating halt decider
>>  > then my code shows that H correctly determines the halt status
>>  > of D.
>>
>
> The quote is correct, and your simulator is incorrect.

*It is good that you understand that the quote is correct*

See my 9:12 AM reply to Richard
it has too many details to keep repeating.
Message-ID: <uognsk$3nggk$1@dont-email.me>

http://al.howardknight.net/
Usenet Article Lookup
<uognsk$3nggk$1@dont-email.me>

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Date: Sat, 20 Jan 2024 09:56:03 -0600
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 by: olcott - Sat, 20 Jan 2024 15:56 UTC

On 1/20/2024 4:07 AM, immibis wrote:
> On 1/20/24 01:36, olcott wrote:
>>
>> The definition of correct simulation simply presumed
>> that pathological self-reference does not change the
>> execution sequence because no one ever bothered to
>> carefully examined this.
>>
>> Naive set theory presumed that its definition of {set}
>> was correct and ZFC proved that it was not correct.
>>
>> Since it is a verified fact that D correctly simulated by
>> H1 depends on H aborting its simulation and H cannot
>> depend on this it is proved that they are not the same.
>>
>>
>
> A Turing machine/initial tape pair has only one execution sequence.

The Peter Linz Proof version of H1 is called H.
The Peter Linz Proof version of H is called embedded_H.

Because ⟨Ĥ⟩ correctly simulated by embedded_H cannot possibly
reach its own simulated final state of ⟨Ĥ.qn⟩ and halt
embedded_H correctly transitions to its own final state of Ĥ.qn.

When Ĥ is applied to ⟨Ĥ⟩
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn

(a) Ĥ.q0 The input ⟨Ĥ⟩ is copied then transitions to embedded_H
(b) embedded_H applied ⟨Ĥ⟩ ⟨Ĥ⟩ (input and copy) simulates ⟨Ĥ⟩ applied to
⟨Ĥ⟩
(c) which begins at its own simulated ⟨Ĥ.q0⟩ to repeat the process

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
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 by: olcott - Sat, 20 Jan 2024 16:06 UTC

On 1/20/2024 9:43 AM, Alan Mackenzie wrote:
> In comp.theory olcott <polcott2@gmail.com> wrote:
>> On 1/20/2024 4:41 AM, Alan Mackenzie wrote:
>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>> On 1/19/2024 6:01 PM, Alan Mackenzie wrote:
>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>>>> On 1/19/2024 4:58 PM, Alan Mackenzie wrote:
>>>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>
>>> [ .... ]
>
>>>>>>>> In other words no one can possibly tell that the above function
>>>>>>>> will not halt until they waited an infinite amount of time and saw
>>>>>>>> that it did not halt. DUMB, DUMB, DUMB, DUMB.
>
>>>>>>> That is why attempting to solve the halting problem with a simulator
>>>>>>> is not a sensible thing to do.
>
>>>>>> The best selling author of textbooks on the theory of computation
>>>>>> disagrees.
>
>>>>> He does not. This author knows full well that a halting decider
>>>>> cannot be built, as do millions of students and graduates world wide,
>>>>> who have seen a proof (or even written one) and appreciate its
>>>>> clarity, simplicity, and finality.
>
>>>>>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X
>
>>>>>> On 10/13/2022 11:46 AM, olcott wrote:
>>>>>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>>>>>> paragraph is correct (he has not agreed to anything else in this
>>>>>>> paper):
>
>>>>>>> If simulating halt decider H correctly simulates its input D until H
>>>>>>> correctly determines that its simulated D would never stop running
>>>>>>> unless aborted then H can abort its simulation of D and correctly
>>>>>>> report that D specifies a non-halting sequence of configurations.
>
>>>>>>> When one accepts this definition of a simulating halt decider then
>>>>>>> my code shows that H correctly determines the halt status of D.
>
>>>>> I haven't seen you define a halting decider of any type over the last
>>>>> few years.
>
>>>> When you ignore what I say THIS DOES NOT COUNT AS ME NOT SAYING IT.
>>>> Professor Sipser agreed that the following definition of a simulating
>>>> halt decider is correct
>
>>> It's like the good professor agreeing that if pigs had wings,
>>> they would fly.
>
>> Not at all. He would not risk his credibility that way.
>> He gave me permission to quote him.
>
> He would not be risking his credibility.

(a) If simulating termination analyzer H correctly determines that D
correctly simulated by H cannot possibly reach its own simulated final
state and terminate normally then

(b) H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.

That you do not understand that the above is correct proves
that you are insufficiently competent to review my work.

There has been a very extensive reviews of this in
comp.theory back in 10/13/2022. You can go see what
many other people have said. It was resolved that
Professor Sipser really meant to agree with these
words.

On 10/13/2022 11:46 AM, olcott wrote:
> MIT Professor Michael Sipser has agreed that the following
> verbatim paragraph is correct.
>
> If simulating halt decider H correctly simulates its input D
> until H correctly determines that its simulated D would never
> stop running unless aborted then H can abort its simulation
> of D and correctly report that D specifies a non-halting
> sequence of configurations.

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[5]

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From: F.Zwarts@HetNet.nl (Fred. Zwarts)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[5]
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 by: Fred. Zwarts - Sat, 20 Jan 2024 16:14 UTC

Op 20.jan.2024 om 15:50 schreef olcott:
> On 1/20/2024 4:17 AM, Fred. Zwarts wrote:

>> It is not D that has a pathological self-reference. D has no
>> self-reference. It is H that has a self-reference. It uses its own
>> address.
>>
>
> *D specifies that it calls its own termination analyzer*
> *so you are wrong, D was intentionally defined to thwart H*

So Olcott can not point to a self-reference in D and he denies that H
has a self-reference, even if Olcott tells us that it uses its own address.
What problem does he/it have with the term self-reference?

I am more and more convinced that Olcott is/uses an AI program that
produces his contributions, because it keeps repeating things that are
wrong and his replies are not logical, or do not have a relation with
the text it refers to.

Re: Correcting the definition of the terms of the halting problem[3]

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From: acm@muc.de (Alan Mackenzie)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
Followup-To: comp.theory
Date: Sat, 20 Jan 2024 16:26:51 -0000 (UTC)
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 by: Alan Mackenzie - Sat, 20 Jan 2024 16:26 UTC

In comp.theory olcott <polcott2@gmail.com> wrote:
> On 1/20/2024 9:43 AM, Alan Mackenzie wrote:
>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>> On 1/20/2024 4:41 AM, Alan Mackenzie wrote:
>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>>> On 1/19/2024 6:01 PM, Alan Mackenzie wrote:
>>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>>>>> On 1/19/2024 4:58 PM, Alan Mackenzie wrote:
>>>>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:

>>>> [ .... ]

>>>>>>>>> In other words no one can possibly tell that the above function
>>>>>>>>> will not halt until they waited an infinite amount of time and saw
>>>>>>>>> that it did not halt. DUMB, DUMB, DUMB, DUMB.

>>>>>>>> That is why attempting to solve the halting problem with a simulator
>>>>>>>> is not a sensible thing to do.

>>>>>>> The best selling author of textbooks on the theory of computation
>>>>>>> disagrees.

>>>>>> He does not. This author knows full well that a halting decider
>>>>>> cannot be built, as do millions of students and graduates world wide,
>>>>>> who have seen a proof (or even written one) and appreciate its
>>>>>> clarity, simplicity, and finality.

>>>>>>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X

>>>>>>> On 10/13/2022 11:46 AM, olcott wrote:
>>>>>>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>>>>>>> paragraph is correct (he has not agreed to anything else in this
>>>>>>>> paper):

>>>>>>>> If simulating halt decider H correctly simulates its input D until H
>>>>>>>> correctly determines that its simulated D would never stop running
>>>>>>>> unless aborted then H can abort its simulation of D and correctly
>>>>>>>> report that D specifies a non-halting sequence of configurations.

>>>>>>>> When one accepts this definition of a simulating halt decider then
>>>>>>>> my code shows that H correctly determines the halt status of D.

>>>>>> I haven't seen you define a halting decider of any type over the last
>>>>>> few years.

>>>>> When you ignore what I say THIS DOES NOT COUNT AS ME NOT SAYING IT.
>>>>> Professor Sipser agreed that the following definition of a simulating
>>>>> halt decider is correct

>>>> It's like the good professor agreeing that if pigs had wings,
>>>> they would fly.

>>> Not at all. He would not risk his credibility that way.
>>> He gave me permission to quote him.

>> He would not be risking his credibility.

You've got no reply to this, I see.

> (a) If simulating termination analyzer H correctly determines that D
> correctly simulated by H cannot possibly reach its own simulated final
> state and terminate normally then

> (b) H can abort its simulation of D and correctly report that D
> specifies a non-halting sequence of configurations.

> That you do not understand that the above is correct proves
> that you are insufficiently competent to review my work.

I understand it fully, thank you very much. You fail to understand it.
If I write "if I correctly state that pigs can fly, then bacon will
correctly go up", then that is the truth, just as much as your (a). It's
inane nonsense, of course, just as your (a) is nonsense.

> There has been a very extensive reviews of this in comp.theory back in
> 10/13/2022. You can go see what many other people have said. It was
> resolved that Professor Sipser really meant to agree with these words.

I read, or at least perused, it at the time. The resolution certainly
was not that Professor Sipser likely agreed with what you would like him
to agree with.

> On 10/13/2022 11:46 AM, olcott wrote:
>> MIT Professor Michael Sipser has agreed that the following
>> verbatim paragraph is correct.

>> If simulating halt decider H correctly simulates its input D
>> until H correctly determines that its simulated D would never
>> stop running unless aborted then H can abort its simulation
>> of D and correctly report that D specifies a non-halting
>> sequence of configurations.

So you've got no reply to the other points I made, then? In particular,
I challenge you to state clearly, once and for all, that you accept the
theorem about the impossibility of a halting decider. Otherwise you're
confirming you are a crank.

> --
> Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
> hits a target no one else can see." Arthur Schopenhauer

--
Alan Mackenzie (Nuremberg, Germany).

Re: Correcting the definition of the terms of the halting problem[5]

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From: polcott2@gmail.com (olcott)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[5]
Date: Sat, 20 Jan 2024 10:29:41 -0600
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 by: olcott - Sat, 20 Jan 2024 16:29 UTC

On 1/20/2024 10:14 AM, Fred. Zwarts wrote:
> Op 20.jan.2024 om 15:50 schreef olcott:
>> On 1/20/2024 4:17 AM, Fred. Zwarts wrote:
>
>>> It is not D that has a pathological self-reference. D has no
>>> self-reference. It is H that has a self-reference. It uses its own
>>> address.
>>>
>>
>> *D specifies that it calls its own termination analyzer*
>> *so you are wrong, D was intentionally defined to thwart H*
>
> So Olcott can not point to a self-reference in D

*The self-reference in DD is when DD calls HH with itself*
Its not that hard, I don't understand why you are not getting it.

> and he denies that H
> has a self-reference, even if Olcott tells us that it uses its own address.
> What problem does he/it have with the term self-reference?
>
> I am more and more convinced that Olcott is/uses an AI program that
> produces his contributions, because it keeps repeating things that are
> wrong and his replies are not logical, or do not have a relation with
> the text it refers to.
>

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: polcott2@gmail.com (olcott)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[3]
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 by: olcott - Sat, 20 Jan 2024 16:34 UTC

On 1/20/2024 10:26 AM, Alan Mackenzie wrote:
> In comp.theory olcott <polcott2@gmail.com> wrote:
>> On 1/20/2024 9:43 AM, Alan Mackenzie wrote:
>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>> On 1/20/2024 4:41 AM, Alan Mackenzie wrote:
>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>>>> On 1/19/2024 6:01 PM, Alan Mackenzie wrote:
>>>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>>>>>>>> On 1/19/2024 4:58 PM, Alan Mackenzie wrote:
>>>>>>>>> In comp.theory olcott <polcott2@gmail.com> wrote:
>
>>>>> [ .... ]
>
>>>>>>>>>> In other words no one can possibly tell that the above function
>>>>>>>>>> will not halt until they waited an infinite amount of time and saw
>>>>>>>>>> that it did not halt. DUMB, DUMB, DUMB, DUMB.
>
>>>>>>>>> That is why attempting to solve the halting problem with a simulator
>>>>>>>>> is not a sensible thing to do.
>
>>>>>>>> The best selling author of textbooks on the theory of computation
>>>>>>>> disagrees.
>
>>>>>>> He does not. This author knows full well that a halting decider
>>>>>>> cannot be built, as do millions of students and graduates world wide,
>>>>>>> who have seen a proof (or even written one) and appreciate its
>>>>>>> clarity, simplicity, and finality.
>
>>>>>>>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X
>
>>>>>>>> On 10/13/2022 11:46 AM, olcott wrote:
>>>>>>>>> MIT Professor Michael Sipser has agreed that the following verbatim
>>>>>>>>> paragraph is correct (he has not agreed to anything else in this
>>>>>>>>> paper):
>
>>>>>>>>> If simulating halt decider H correctly simulates its input D until H
>>>>>>>>> correctly determines that its simulated D would never stop running
>>>>>>>>> unless aborted then H can abort its simulation of D and correctly
>>>>>>>>> report that D specifies a non-halting sequence of configurations.
>
>>>>>>>>> When one accepts this definition of a simulating halt decider then
>>>>>>>>> my code shows that H correctly determines the halt status of D.
>
>>>>>>> I haven't seen you define a halting decider of any type over the last
>>>>>>> few years.
>
>>>>>> When you ignore what I say THIS DOES NOT COUNT AS ME NOT SAYING IT.
>>>>>> Professor Sipser agreed that the following definition of a simulating
>>>>>> halt decider is correct
>
>>>>> It's like the good professor agreeing that if pigs had wings,
>>>>> they would fly.
>
>>>> Not at all. He would not risk his credibility that way.
>>>> He gave me permission to quote him.
>
>>> He would not be risking his credibility.
>
> You've got no reply to this, I see.
>
>> (a) If simulating termination analyzer H correctly determines that D
>> correctly simulated by H cannot possibly reach its own simulated final
>> state and terminate normally then
>
>> (b) H can abort its simulation of D and correctly report that D
>> specifies a non-halting sequence of configurations.
>
>> That you do not understand that the above is correct proves
>> that you are insufficiently competent to review my work.
>
> I understand it fully, thank you very much. You fail to understand it.
> If I write "if I correctly state that pigs can fly, then bacon will
> correctly go up", then that is the truth, just as much as your (a). It's
> inane nonsense, of course, just as your (a) is nonsense.
>
>> There has been a very extensive reviews of this in comp.theory back in
>> 10/13/2022. You can go see what many other people have said. It was
>> resolved that Professor Sipser really meant to agree with these words.
>
> I read, or at least perused, it at the time. The resolution certainly
> was not that Professor Sipser likely agreed with what you would
> like him to agree with.
>

*That is the strawman deception and you know it*
You claimed that he agreed with nonsense and this
is provably false. He agreed that my verbatim
words are correct. He did not agree with nonsense.

--
Copyright 2023 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Re: Correcting the definition of the terms of the halting problem[3]

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From: news@immibis.com (immibis)
Newsgroups: sci.logic,comp.theory
Subject: Re: Correcting the definition of the terms of the halting problem[3]
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 by: immibis - Sat, 20 Jan 2024 17:10 UTC

On 1/20/24 16:38, olcott wrote:
> On 1/20/2024 4:04 AM, immibis wrote:
>> On 1/20/24 01:55, olcott wrote:
>>>
>>> Begin Local Halt Decider Simulation        Execution Trace Stored
>>> at:113027
>>> [00001c42][00113013][00113017] 55          push ebp
>>> [00001c43][00113013][00113017] 8bec        mov ebp,esp
>>> [00001c45][0011300f][00102fe3] 51          push ecx
>>> [00001c46][0011300f][00102fe3] 8b4508      mov eax,[ebp+08] ; DD
>>> [00001c49][0011300b][00001c42] 50          push eax         ; DD
>>> [00001c4a][0011300b][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
>>> [00001c4d][00113007][00001c42] 51          push ecx         ; DD
>>> [00001c4e][00113003][00001c53] e80ff7ffff  call 00001362    ; HH
>>> New slave_stack at:14da47
>>> [00001c42][0015da3b][0015da3f] 55          push ebp
>>> [00001c43][0015da3b][0015da3f] 8bec        mov ebp,esp
>>> [00001c45][0015da37][0014da0b] 51          push ecx
>>> [00001c46][0015da37][0014da0b] 8b4508      mov eax,[ebp+08] ; DD
>>> [00001c49][0015da33][00001c42] 50          push eax         ; DD
>>> [00001c4a][0015da33][00001c42] 8b4d08      mov ecx,[ebp+08] ; DD
>>> [00001c4d][0015da2f][00001c42] 51          push ecx         ; DD
>>> [00001c4e][0015da2b][00001c53] e80ff7ffff  call 00001362    ; HH
>>> Local Halt Decider: Recursion Simulation Detected Simulation Stopped
>>>
>>> That you cannot tell that the above specifies
>>> non-halting behavior makes you a dunderhead.
>>>
>>
>> This trace dishonestly ignores the instructions that tell HH to check
>> for non-halting repeated patterns.
>
> Nothing that HH can possibly do can cause DD correctly
> simulated by HH to reach its own simulated final state.

HH detects a non-halting pattern and returns 0, which causes DD to reach
its final state.

Re: Correcting the definition of the terms of the halting problem[3]

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 by: immibis - Sat, 20 Jan 2024 17:11 UTC

On 1/20/24 16:43, olcott wrote:
> On 1/20/2024 4:04 AM, immibis wrote:
>> On 1/20/24 02:26, olcott wrote:
>>>
>>> The full state of D was repeated.
>>> The only thing that changed was the stack address.
>>>
>> You think the stack address doesn't matter?
>
> That each process context has its own stack cannot possibly
> have any effect on the halt status determination.
>
> That you don't know this proves that you are insufficiently
> technically competent to review my work.
>

You keep saying the code address matters even if the code at that
address is identical.

By the same logic the stack address matters, even if the data on the
stack is identical.

Re: Correcting the definition of the terms of the halting problem[3]

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 by: immibis - Sat, 20 Jan 2024 17:11 UTC

On 1/20/24 16:56, olcott wrote:
> On 1/20/2024 4:07 AM, immibis wrote:
>> On 1/20/24 01:36, olcott wrote:
>>>
>>> The definition of correct simulation simply presumed
>>> that pathological self-reference does not change the
>>> execution sequence because no one ever bothered to
>>> carefully examined this.
>>>
>>> Naive set theory presumed that its definition of {set}
>>> was correct and ZFC proved that it was not correct.
>>>
>>> Since it is a verified fact that D correctly simulated by
>>> H1 depends on H aborting its simulation and H cannot
>>> depend on this it is proved that they are not the same.
>>>
>>>
>>
>> A Turing machine/initial tape pair has only one execution sequence.
>
> The Peter Linz Proof version of H1 is called H.
> The Peter Linz Proof version of H is called embedded_H.
>
> Because ⟨Ĥ⟩ correctly simulated by embedded_H cannot possibly
> reach its own simulated final state of ⟨Ĥ.qn⟩ and halt
> embedded_H correctly transitions to its own final state of Ĥ.qn.
>
> When Ĥ is applied to ⟨Ĥ⟩
> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>
> (a) Ĥ.q0 The input ⟨Ĥ⟩ is copied then transitions to embedded_H
> (b) embedded_H applied ⟨Ĥ⟩ ⟨Ĥ⟩ (input and copy) simulates ⟨Ĥ⟩ applied to
> ⟨Ĥ⟩
> (c) which begins at its own simulated ⟨Ĥ.q0⟩ to repeat the process
>
>
Nonetheless, it is a verified fact that a Turing machine/initial tape
pair has only one execution sequence.

Re: Correcting the definition of the terms of the halting problem[5]

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From: news@immibis.com (immibis)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[5]
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 by: immibis - Sat, 20 Jan 2024 17:12 UTC

On 1/20/24 15:50, olcott wrote:
> DD correctly simulated by HH is a different computation
> than the directly executed DD(DD).

Thank you for confirming this. This proves that HH is an incorrect
simulator. NEXT!

Re: Correcting the definition of the terms of the halting problem[5]

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From: news@immibis.com (immibis)
Newsgroups: comp.theory,sci.logic
Subject: Re: Correcting the definition of the terms of the halting problem[5]
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 by: immibis - Sat, 20 Jan 2024 17:13 UTC

On 1/20/24 17:14, Fred. Zwarts wrote:
>
> I am more and more convinced that Olcott is/uses an AI program that
> produces his contributions, because it keeps repeating things that are
> wrong and his replies are not logical, or do not have a relation with
> the text it refers to.
>

Unfortunately, olcott has been around much longer than GPT-2.

Re: Correcting the definition of the terms of the halting problem[5]

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From: news@immibis.com (immibis)
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Subject: Re: Correcting the definition of the terms of the halting problem[5]
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 by: immibis - Sat, 20 Jan 2024 17:13 UTC

On 1/20/24 17:29, olcott wrote:
> On 1/20/2024 10:14 AM, Fred. Zwarts wrote:
>> Op 20.jan.2024 om 15:50 schreef olcott:
>>> On 1/20/2024 4:17 AM, Fred. Zwarts wrote:
>>
>>>> It is not D that has a pathological self-reference. D has no
>>>> self-reference. It is H that has a self-reference. It uses its own
>>>> address.
>>>>
>>>
>>> *D specifies that it calls its own termination analyzer*
>>> *so you are wrong, D was intentionally defined to thwart H*
>>
>> So Olcott can not point to a self-reference in D
>
> *The self-reference in DD is when DD calls HH with itself*

DD doesn't call HH with itself. DD calls HH with DD's argument, twice.

Meanwhile, HH has an actual self-reference.

> Its not that hard, I don't understand why you are not getting it.

Its not that hard, I don't understand why you are not getting it.


devel / comp.theory / Re: Correcting the definition of the terms of the halting problem[3]

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